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PDF HA-2556 Data sheet ( Hoja de datos )

Número de pieza HA-2556
Descripción 57MHz/ Wideband/ Four Quadrant/ Voltage Output Analog Multiplier
Fabricantes Intersil Corporation 
Logotipo Intersil Corporation Logotipo



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No Preview Available ! HA-2556 Hoja de datos, Descripción, Manual

Data Sheet
HA-2556
September 1998 File Number 2477.5
57MHz, Wideband, Four Quadrant,
Voltage Output Analog Multiplier
The HA-2556 is a monolithic, high speed, four quadrant,
analog multiplier constructed in the Intersil Dielectrically
Isolated High Frequency Process. The voltage output
simplifies many designs by eliminating the current-to-voltage
conversion stage required for current output multipliers. The
HA-2556 provides a 450V/µs slew rate and maintains
52MHz and 57MHz bandwidths for the X and Y channels
respectively, making it an ideal part for use in video systems.
The suitability for precision video applications is
demonstrated further by the Y Channel 0.1dB gain flatness
to 5.0MHz, 1.5% multiplication error, -50dB feedthrough and
differential inputs with 8µA bias current. The HA-2556 also
has low differential gain (0.1%) and phase (0.1o) errors.
The HA-2556 is well suited for AGC circuits as well as mixer
applications for sonar, radar, and medical imaging
equipment. The HA-2556 is not limited to multiplication
applications only; frequency doubling, power detection, as
well as many other configurations are possible.
For MIL-STD-883 compliant product consult the
HA-2556/883 datasheet.
Ordering Information
PART NUMBER
HA3-2556-9
HA9P2556-9
HA1-2556-9
TEMP.
RANGE (oC)
PACKAGE
-40 to 85 16 Ld PDIP
-40 to 85 16 Ld SOIC
-40 to 85 16 Ld CERDIP
PKG.
NO.
E16.3
M16.3
F16.3
Pinout
HA-2556
(PDIP, CERDIP, SOIC)
TOP VIEW
GND 1
VREF 2
VYIOB 3
VYIOA 4
VY+ 5
VY- 6
V- 7
VOUT 8
REF
X
Y
+
Σ
-
Z
16 VXIOA
15 VXIOB
14 NC
13 VX+
12 VX-
11 V+
10 VZ-
9 VZ+
Features
• High Speed Voltage Output . . . . . . . . . . . . . . . . . 450V/µs
• Low Multiplication Error . . . . . . . . . . . . . . . . . . . . . . .1.5%
• Input Bias Currents. . . . . . . . . . . . . . . . . . . . . . . . . . . 8µA
• 5MHz Feedthrough. . . . . . . . . . . . . . . . . . . . . . . . . . -50dB
• Wide Y Channel Bandwidth . . . . . . . . . . . . . . . . . . 57MHz
• Wide X Channel Bandwidth . . . . . . . . . . . . . . . . . . 52MHz
• VY 0.1dB Gain Flatness . . . . . . . . . . . . . . . . . . . . 5.0MHz
Applications
• Military Avionics
• Missile Guidance Systems
• Medical Imaging Displays
• Video Mixers
• Sonar AGC Processors
• Radar Signal Conditioning
• Voltage Controlled Amplifier
• Vector Generators
Functional Block Diagram
VX+
+
-
VX-
1/SF
VY+
+
-
VY-
HA-2556
X
VOUT
A
+
-
Y
Z
VZ+
+
-
VZ-
NOTE: The transfer equation for the HA-2556 is:
(VX+ -VX-) (VY+ -VY-) = SF (VZ+ -VZ-),
where SF = Scale Factor = 5V; VX, VY,
VZ = Differential Inputs.
1 CAUTION: These devices are sensitive to electrostatic discharge; follow proper IC Handling Procedures.
1-888-INTERSIL or 321-724-7143 | Copyright © Intersil Corporation 1999

1 page




HA-2556 pdf
HA-2556
Typical Applications
Let’s first examine the Balance Concept as it applies to the
standard multiplier configuration (Figure 2).
A
VX+
+
-
VX-
HA-2556
X
VOUT
A
1/5V
+
B
VY+
+
Y
-
Z
VZ +
+
--
W
VY- VZ-
FIGURE 2. MULTIPLIER
Signals A and B are input to the multiplier and the signal W
is the result. By substituting the signal values into the
Balance equation you get:
(A) x (B) = 5(W)
And solving for W:
W = A------5x-----B--
Notice that the output (W) enters the equation in the
feedback to the Z stage. The Balance Equation does not test
for stability, so remember that you must provide negative
feedback. In the multiplier configuration, the feedback path is
connected to VZ+ input, not VZ-. This is due to the inversion
that takes place at the summing node just prior to the output
amplifier. Feedback is not restricted to the Z stage, other
feedback paths are possible as in the Divider Configuration
shown in Figure 3.
VX+
+
-
VX-
HA-2556
X
VOUT
A
W
+
1/5V
B
VY+
+
Y
-
Z
VZ +
+
-
VY-
-
VZ -
A
FIGURE 3. DIVIDER
Inserting the signal values A, B and W into the Balance
Equation for the divider configuration yields:
(-W) (B) = 5V x (-A)
Solving for W yields:
W = 5--B--A--
Notice that, in the divider configuration, signal B must remain
0 (positive) for the feedback to be negative. If signal B is
negative, then it will be multiplied by the VX- input to produce
positive feedback and the output will swing into the rail.
Signals may be applied to more than one input at a time as
in the Squaring configuration in Figure 4:
Here the Balance equation will appear as:
(A) x (A) = 5(W)
A
VX+
+
-
VX-
HA-2556
X
VOUT
A
W
+
1/5V
VY+
+
-
Y
-
Z
VZ +
+
-
VY - VZ-
FIGURE 4. SQUARE
Which simplifies to:
W = A--5---2-
The last basic configuration is the Square Root as shown in
Figure 5. Here feedback is provided to both X and Y inputs.
VX+
+
-
VX-
1/5V
VY+
+
-
VY-
HA-2556
X
+
-
YZ
VOUT
A
VZ +
+
-
VZ -
FIGURE 5. SQUARE ROOT (FOR A > 0)
W
A
The Balance equation takes the form:
(W) × (W) = 5(A)
Which equates to:
W = 5A
The four basic configurations (Multiply, Divide, Square and
Square Root) as well as variations of these basic circuits
have many uses.
Frequency Doubler
For example, if ACos(ωτ) is substituted for signal A in the
Square function, then it becomes a Frequency Doubler and
the equation takes the form:
(ACos(ωτ)) × (ACos(ωτ)) = 5(W)
And using some trigonometric identities gives the result:
W = -A1---0-2- (1 + Cos(2ωτ))
5

5 Page





HA-2556 arduino
Typical Performance Curves (Continued)
8
HA-2556
200
4 100
00
-4
-8
0ns
VX = ±4V PULSE
VY = 5VDC
500ns
2V/DIV.; 100ns/DIV.
FIGURE 28. LARGE SIGNAL RESPONSE
1µs
4 Y CHANNEL = 10VP-P
X CHANNEL = 5VDC
3
2
1
0
-1
-2
-3
-4 -3dB
AT 32.5MHz
10K 100K
1M
10M
FREQUENCY (Hz)
FIGURE 30. Y CHANNEL FULL POWER BANDWIDTH
-100
-200
0ns
VY = ±100mV PULSE
VX = 5VDC
250ns
50mV/DIV.; 50ns/DIV.
FIGURE 29. SMALL SIGNAL RESPONSE
500ns
4 Y CHANNEL = 4VP-P
X CHANNEL = 5VDC
3
2
1
0
-1
-2
-3
-4
10K 100K
1M
10M
FREQUENCY (Hz)
FIGURE 31. Y CHANNEL FULL POWER BANDWIDTH
4 X CHANNEL = 10VP-P
Y CHANNEL = 5VDC
3
2
1
0
-1
-2
-3
-4
10K 100K 1M
10M
FREQUENCY (Hz)
FIGURE 32. X CHANNEL FULL POWER BANDWIDTH
11
4 X CHANNEL = 4VP-P
Y CHANNEL = 5VDC
3
2
1
0
-1
-2
-3
-4
10K 100K
1M
10M
FREQUENCY (Hz)
FIGURE 33. X CHANNEL FULL POWER BANDWIDTH

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